8x^2+56x-147=0

Solution for 8x^2+56x-147=0 equation:

8x^2+56x-147=0

a = 8; b = 56; c = -147;
Δ = b2-4ac
Δ = 562-4·8·(-147)
Δ = 7840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7840}=\sqrt{784*10}=\sqrt{784}*\sqrt{10}=28\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-28\sqrt{10}}{2*8}=\frac{-56-28\sqrt{10}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+28\sqrt{10}}{2*8}=\frac{-56+28\sqrt{10}}{16}
$